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$result = mysql_query("SELECT * FROM Cno");//查找 沒(méi)有執(zhí)行成功 mysql_fetch_array() expects parameter 1 to be resource, boolean given in D:\xampp\htdocs\4.php on line 12 請(qǐng)問(wèn)是什么錯(cuò)誤？如何改正？謝謝大家啊~ 代碼如下： <?php $con = mysql_connect("localhost","root ",""); //通過(guò)服務(wù)器locahost建立連接，用戶名為root，無(wú)密碼 if (!$con) { die('Could not connect: ' . mysql_error()); }//如果不成功，顯示錯(cuò)誤 mysql_select_db("crms", $con);//選擇數(shù)據(jù)庫(kù) $result = mysql_query("SELECT * FROM Cno");//查找 while($row = mysql_fetch_array($result))//打印 { echo $row['Cno'] . " " . $row['Cno']; echo "<br />"; } mysql_close($con); ?> |
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來(lái)自： 昵稱13036064 > 《php》
