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      JAVA int 強(qiáng)制類型轉(zhuǎn)換錯(cuò)誤提示(Cannot cast from Object to int)

       quasiceo 2015-12-13
      在將ANDROID源碼導(dǎo)入eclipse時(shí),出錯(cuò)提示如下:
          public void addActiveCid(int cid) {
              if (cidActiveList == null) {
                  cidActiveList = new ArrayList();
              }
              for (int i=0;i
                  if(cid == cidActiveList.get(i)) {                 // 行 657
                      return;
                  }
              }
              cidActiveList.add(cid);
              Log.d(LOG_TAG, "[" + phone.getPhoneId() + "]addActiveCid("+cid+") cidActive("+cidActive+") List("+cidActiveList+")");
          }
          public void removeActiveCid(int cid) {
              if (cidActiveList != null) {
                  for (int i=0;i
                      if(cid == cidActiveList.get(i)) {          // 行667.
                          cidActiveList.remove(i);
                      }
                  }
              }

      Incompatible operand types int and Object    DataConnectionTracker.java   /check/frameworks/base/telephony/java/com/android/internal/telephony    line 657    Java Problem

      Incompatible operand types int and Object    DataConnectionTracker.java   /check/frameworks/base/telephony/java/com/android/internal/telephony    line 667    Java Problem

      將 if(cid == cidActiveList.get(i))加入強(qiáng)制轉(zhuǎn)換int后,即

                 if(cid == (int)cidActiveList.get(i))
      又出現(xiàn)如下錯(cuò)誤提示:
      Cannot cast from Object to int    DataConnectionTracker.java   /check/frameworks/base/telephony/java/com/android/internal/telephony    line 657    Java Problem

      最后在網(wǎng)上找了一翻,最終改為如下, 即問(wèn)題解決。
              if(cid == (Integer)cidActiveList.get(i))

      特此記錄,以備后忘。

      (int) (v.getTag())  ==》
      (Integer) (v.getTag())

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