我正在使用envers來審核我的ParameterToValue實(shí)體.它的屬性“containerId”,“containerType”,“parameterId”在映射的數(shù)據(jù)庫表“values_for_params”(常規(guī)Hibernate表)中顯示為列,在生成的“values_for_params_AUD”DB表中缺少.我需要能夠獲得給定的(containerId,containerType,parameterId)的歷史“值”.

ParameterToValue類：

@Audited
public class ParameterToValue extends BasicValueHolder {
private Long containerId;
private ContainerType containerType;
private Long parameterId;

public ParameterToValue(ContainerID containerId, Long parameterId, Value value) {
    super(value);
    this.containerId = containerId.getContainerId();
    this.parameterId = parameterId;
    containerType = containerId.getContainerType();
}

ParameterToValue() {
}

public Long getParameterId() {
    return parameterId;
}

public void setParameterId(Long parameterId) {
    this.parameterId = parameterId;
}

public Value getValue() {
    return value;
}

public void setValue(Value value) {
    this.value = value;
}

public Long getContainerId() {
    return containerId;
}

public void setContainerId(Long containerId) {
    this.containerId = containerId;
}

public ContainerType getContainerType() {
    return containerType;
}

public void setContainerType(ContainerType containerType) {
    this.containerType = containerType;
}
}

Hibernate映射定義：

<class name="platform.server.dataservices.model.ParameterToValue" table="values_for_params">
    <cache usage="read-write" include="all" />
    <id name="id" column="ID">
        <generator class="native"/>
    </id>
    <properties name="uniqueProps" unique="true">
        <property name="containerId" index="ParamValsContainerIdIndx"/>
        <property name="parameterId" index="ParamValsParamIdIndx"/>
        <property name="containerType" column="CONTAINER_TYPE">
            <type name="org.hibernate.type.EnumType">
                <param name="enumClass">platform.server.dataservices.model.ContainerType</param>
                <param name="type">4</param>
                <!-- 12 = string, 5 = smallint, 4 = integer, default 4 -->
            </type>
        </property>
    </properties>

    <many-to-one name="value" cascade="all" lazy="false" unique="true" index="PRM_VAL_IDX"/>
</class>

在MySQL中顯示CREATE TABLE values_for_params：

CREATE TABLE `values_for_params` (
  ID` bigint(20) NOT NULL AUTO_INCREMENT,
  `containerId` bigint(20) DEFAULT NULL,
  `parameterId` bigint(20) DEFAULT NULL,
  `CONTAINER_TYPE` int(11) DEFAULT NULL,
  `value` bigint(20) DEFAULT NULL,
PRIMARY KEY (`ID`),
UNIQUE KEY `value` (`value`),
UNIQUE KEY `containerId` (`containerId`,`parameterId`,`CONTAINER_TYPE`),
KEY `ParamValsParamIdIndx` (`parameterId`),
KEY `ParamValsContainerIdIndx` (`containerId`),
KEY `PRM_VAL_IDX` (`value`),
KEY `FKE02CB4F981565307` (`value`),
CONSTRAINT `FKE02CB4F981565307` FOREIGN KEY (`value`) REFERENCES `value` (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=28 DEFAULT CHARSET=utf8

在MySQL中顯示CREATE TABLE values_for_params_AUD：

CREATE TABLE `values_for_params_AUD` (
  `ID` bigint(20) NOT NULL,
  `REV` int(11) NOT NULL,
  `REVTYPE` tinyint(4) DEFAULT NULL,
  `value` bigint(20) DEFAULT NULL,
PRIMARY KEY (`ID`,`REV`),
KEY `FKE093BE4AEB88DFB` (`REV`),
CONSTRAINT `FKE093BE4AEB88DFB` FOREIGN KEY (`REV`) REFERENCES `DesignRevisionEntity`     (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

解決方法:

固定.如果有人需要答案：

問題是,envers忽略了在properties標(biāo)簽內(nèi)寫的任何內(nèi)容.當(dāng)我以這種方式刪除標(biāo)簽時(shí)：

<properties name="uniqueProps" unique="true">
    <property name="containerId" index="ParamValsContainerIdIndx"/>
    <property name="parameterId" index="ParamValsParamIdIndx"/>
    <property name="containerType" column="CONTAINER_TYPE">
        <type name="org.hibernate.type.EnumType">
            <param name="enumClass">platform.server.dataservices.model.ContainerType</param>
            <param name="type">4</param>
        </type>
    </property>
</properties>

變成了：

<property name="containerId" index="ParamValsContainerIdIndx"/>
<property name="parameterId" index="ParamValsParamIdIndx"/>
<property name="containerType" column="CONTAINER_TYPE">
  <type name="org.hibernate.type.EnumType">
    <param name="enumClass">platform.server.dataservices.model.ContainerType</param>
    <param name="type">4</param>
  </type>
</property>

這樣,所有屬性都被審計(jì),但我仍然需要三元組(containerId,parameterId,containerType)是唯一的.最終的解決方案是：

<property name="containerId" index="ParamValsContainerIdIndx"/>
<property name="parameterId" index="ParamValsParamIdIndx"/>
<property name="containerType" column="CONTAINER_TYPE">
  <type name="org.hibernate.type.EnumType">
    <param name="enumClass">platform.server.dataservices.model.ContainerType</param>
    <param name="type">4</param>
  </type>
</property>

<properties name="uniqueProps" unique="true">
  <property name="containerId" insert="false" update="false"/>
  <property name="parameterId" insert="false" update="false"/>
  <property name="containerType" insert="false" update="false"/>
</properties>